73 lines
2.1 KiB
Python
73 lines
2.1 KiB
Python
import datetime
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import re
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def current():
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return datetime.datetime.now()
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def current_timestamp():
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return int(datetime.datetime.now().timestamp() * 1000)
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def timestamp2datetime(timestamp):
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return datetime.datetime.fromtimestamp(timestamp / 1000.0)
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def is_time_difference_greater_than(timestamp1, timestamp2, hours=0, minutes=0, seconds=0, milliseconds=0):
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"""
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判断两个时间戳的时间差是否大于指定的小时、分钟和秒数
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参数:
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timestamp1 (int): 第一个时间戳
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timestamp2 (int): 第二个时间戳
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hours (int): 要比较的小时数，默认是0小时
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minutes (int): 要比较的分钟数，默认是0分钟
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seconds (int): 要比较的秒数，默认是0秒
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返回:
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bool: 如果时间差大于指定的小时、分钟和秒数返回True，否则返回False
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"""
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# 将时间戳转换为 datetime 对象
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time1 = timestamp2datetime(timestamp1)
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time2 = timestamp2datetime(timestamp2)
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# 计算时间差
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time_difference = abs(time2 - time1)
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# 计算指定的时间差值
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threshold = datetime.timedelta(hours=hours, minutes=minutes, seconds=seconds, milliseconds=milliseconds)
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# 判断时间差是否大于指定的时间
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return time_difference > threshold
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def parse_time_string(time_str):
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# 定义支持的时间单位
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time_units = {
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'd': 'days',
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'h': 'hours',
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'min': 'minutes',
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's': 'seconds',
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'ms': 'milliseconds'
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}
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# 使用正则表达式匹配数字和单位的模式
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matches = re.findall(fr"(\d+)({'|'.join(time_units.keys())})", time_str)
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if not matches:
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raise ValueError(f"Invalid time string format: {time_str}")
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result = {}
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for value, unit in matches:
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if unit in time_units:
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result[time_units[unit]] = int(value)
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else:
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raise ValueError(f"Unsupported unit: {unit}")
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return result
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def to_milliseconds(days=0, hours=0, minutes=0, seconds=0, milliseconds=0):
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return days * 24 * 60 * 60 * 1000 + hours * 60 * 60 * 1000 + minutes * 60 * 1000 + seconds * 1000 + milliseconds
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